If SSXY = −16.32 and SSX = 40.00 for a set of data points, then what is the value of the slope for the best-fitting linear equation? a. −0.41 b. −2.45 c. positive d. There is not enough information; you would also need to know the value of SSY.

Respuesta :

Answer: a. −0.41

Step-by-step explanation:

The slope for the best-fitting linear equation is given by :-

[tex]b=\dfrac{SS_{xy}}{SS_x}[/tex]

where , [tex]SS_x[/tex] =sum of squared deviations from the mean of X.

[tex]SS_{xy}[/tex] = correlation between y and x in terms of the corrected sum of products.

As per given , we have

[tex]SS_x=10.00[/tex]

[tex]SS_{xy}=-16.32[/tex]

Then, the value of the slope for the best-fitting linear equation will be

[tex]b=\dfrac{-16.32}{40.00}=-0.408\approx -0.41[/tex]

Hence, the value of the slope for the best-fitting linear equation= -0.41

So the correct answer is a. −0.41 .

The value of the slope for the best-fitting linear equation is -0.41

The given parameters are:

[tex]SS_{xy} = -16.32[/tex] --- the correlation between y and x

[tex]SS_{x} = 40.00[/tex] --- the sum of squared deviations from the mean of X.

The slope (b) is calculated using the following formula

[tex]b = \frac{SS_{xy}}{SS_x}[/tex]

Substitute values for SSxy and SSx

[tex]b = \frac{-16.32}{40.00}[/tex]

Divide -16.32 by 40.00

[tex]b = -0.408[/tex]

Approximate

[tex]b = -0.41[/tex]

Hence, the value of the slope for the best-fitting linear equation is -0.41

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