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In a Young’s double-slit experiment, a thin sheet of mica is placed over one of the two slits. As a result, the center of the fringe pattern (on the screen) shifts by an amount corresponding to 30 dark bands. The wavelength of the light in this experiment is 480 nm and the index of the mica is 1.60. The mica thickness is:

Respuesta :

Answer:0.024 mm

Explanation:

Given

Fringe shifts by an amount to 30 dark bands i.e. [tex]m=30[/tex]

Wavelength [tex]\lambda =480 nm[/tex]

refractive index of mica [tex]n_2=1.6[/tex]

refractive index of air [tex]n_1=1[/tex]

Phase difference is given by

[tex]m=\frac{t\left [ n_2-n_1\right ]}{\lambda }[/tex]

[tex]30=\frac{t\left [ 1.6-1\right ]}{480\times 10^{-9}}[/tex]

[tex]t=\frac{30\times 480\times 10^{-9}}{1.6-1}[/tex]

[tex]t=0.024\ mm[/tex]