Answer:
The distance of frame from each side of the wall so that it is at centered is 7.5 feet
Step-by-step explanation:
Given as :
The measure of the wall = 17[tex]\dfrac{3}{4}[/tex] feet
i.e The measure of the wall =[tex]\dfrac{71}{4}[/tex] feet
The measure of the picture = 2[tex]\dfrac{3}{4}[/tex] feet
i.e The measure of the picture =[tex]\dfrac{11}{4}[/tex] feet
Let The distance from each side of wall so that frame at centered = x feet
Now, According to question
x = The measure of the wall - measure of the picture
Or, x = [tex]\dfrac{71}{4}[/tex] feet - [tex]\dfrac{11}{4}[/tex] feet
Or, x = [tex]\dfrac{71 - 11}{4}[/tex] feet
Or, x = [tex]\dfrac{60}{4}[/tex] feet
∴ x = 15 feet
Now, For each side so that frame st centered = [tex]\dfrac{15}{2}[/tex] feet
Or, For each side so that frame st centered = 7.5 feet
Hence,The distance of frame from each side of the wall so that it is at centered is 7.5 feet Answer