A glass column is filled with mercury and inverted in a pool of mercury. The mercury column stabilizes at a height of 735 mm above the pool of mercury. What is the pressure of the atmosphere?

Respuesta :

Answer:

[tex] 735 mm Hg = 0.967 atm= 97991.940 Pa=97.992Pa[/tex]

Explanation:

Previous concepts

Atmospheric pressure is defined as "the force per unit area exerted against a surface by the weight of the air above that surface".

Torricelli shows that we can calculate the atmosphric pressure with a glass tube inside of a tank and with the height we can find the pressure with the relation

[tex]P_{atm}=\rho_{Hg} g h[/tex]

Solution to the problem

For this case we can use the following conversion factor:

[tex]1 atm = 760 mm Hg[/tex]

And if we convert the 735 mm Hg to atm we got this:

[tex]735 mm Hg * \frac{1atm}{760 mm Hg}=0.967 atm[/tex]

And also we can convert this value to Pa and Kpa since we have this conversion factor:

[tex] 1 atm =101325 Pa[/tex]

And if we apply the conversion we got:

[tex]0.967 atm *\frac{101325 Pa}{1 atm}=97991.940 Pa[/tex]

And that correspond to 97.99 Kpa.

Finally we can express the atmospheric pressure on different units for this case :

[tex] 735 mm Hg = 0.967 atm= 97991.940 Pa=97.992Pa[/tex]

The atmospheric pressure (atm) resulting from the mercury column is 0.967 atm.

The given parameters;

  • the height of the mercury column, h = 735 mm Hg

The atmospheric pressure (atm) resulting from the mercury column is calculated as follows;

760 mmHg ------- 1 atm

735 mmHg -------- ?

[tex]= \frac{735 \ \times \ 1 atm}{760} \\\\= 0.967 \ atm[/tex]

Thus, the atmospheric pressure (atm) resulting from the mercury column is 0.967 atm.

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