To solve this problem we will use the three requested concepts: Wavelength, frequency and period.
The wavelength is the distance between each crest, therefore it is already given and is 0.8m
The correct answer is C.
The frequency can be described as a relationship between wave speed and wavelength therefore
[tex]f = \frac{v}{\lambda}[/tex]
[tex]f = \frac{2.2}{0.8}[/tex]
[tex]f = 2.75Hz \approx 2.8Hz[/tex]
The correct answer is B.
The period is the inverse of the frequency therefore
[tex]T = \frac{1}{f}[/tex]
[tex]T = \frac{1}{2.8}[/tex]
[tex]T = 0.35s[/tex]
The correct answer is B.
(a) The wavelength of the wave is 0.80m and the right option is c.
(b) The frequency of the wave is 2.8 Hz and the right option is b.
(c) The period of the wave is 0.36 s and the right option is b
(a) The distance between successive wave crests = wavelength of the wave
From the question,
(a) Wavelength = 0.80 m
Hence the wavelength = 0.80 m
(b) Using,
V = λf.............. Equation 1
Where V = Velocity of the wave, λ = wavelength of the wave, f = frequency of the wave.
f = V/λ.................... Equation 2
Given: V = 2.2 m/s, λ = 0.80 m
Substitute these values into equation 2
f = 2.2/0.8
f = 2.75 Hz.
f ≈ 2.8 Hz
Hence the frequency of the wave is 2.8 Hz
(c) f = 1/T.............. Equation 3
Where T = period.
Therefore,
T = 1/f .................. 4
Given: f = 2.8 Hz,
T = 1/2.8
T = 0.357
T ≈ 0.36 s
Hence the period of the wave = 0.36 s
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