Respuesta :
Answer:
Equations written in slope-intercept have the form: y = m x + b where m is the slope and b is the y intercept point. Horizontal lines have a slope of 0 (similar to a flat ground surface) and m would be 0 for these lines.
Also, the y intercept is the point through which the horizontal line would pass. In this case, the y intercept or b is -11.
The equation would then be
y = 0x + (-11)
OR
y = 0x -11
Often we write the equation without the "0x" term:
y= -11
Answer: y=0x-11
Let’s start by writing the model equation for slope-intercept:
y=mx+b
M-slope
X-variable
B- y-intercept
Since we know that m is the slope, let’s substitute that into the equation
y=mx+b
y=0x+b
Now we need to solve for b. Since we are given a point, let’s substitute that point into our current equation and solve for b
y=0x+b
*substitute y and x of point*
-11=0(0)+b
*multiply 0 and 0*
-11=0+b
-11=b
Let’s add that into the equation
y=mx+b
y=0x+b
y=0x-11
Hope this helps comment below for more questions :)
Let’s start by writing the model equation for slope-intercept:
y=mx+b
M-slope
X-variable
B- y-intercept
Since we know that m is the slope, let’s substitute that into the equation
y=mx+b
y=0x+b
Now we need to solve for b. Since we are given a point, let’s substitute that point into our current equation and solve for b
y=0x+b
*substitute y and x of point*
-11=0(0)+b
*multiply 0 and 0*
-11=0+b
-11=b
Let’s add that into the equation
y=mx+b
y=0x+b
y=0x-11
Hope this helps comment below for more questions :)