Answer:
1.50×10²¹ atoms of C
Explanation:
First of all, let's convert the mass into moles (mass (g) / molar mass)
0.030 g / 12 g/mol = 2.5×10⁻³ moles
Now, we can apply the Avogadro Number
1 mol has __ 6.02×10²³ atoms
2.5×10⁻³ mol would have (2.5×10⁻³ mol . NA) = 1.50×10²¹
Answer: There are [tex]0.015\times 10^{23}[/tex] atoms of carbon
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{0.03g}{12g/mol}=0.0025moles[/tex] (1g=1000mg)
1 mole of carbon atom contains = [tex]6.023\times 10^{23}[/tex] atoms of carbon
0.0025 mole of carbon contain = [tex]\frac{6.023\times 10^{23}}{1}\times 0.0025=0.015\times 10^{23}[/tex] atoms of carbon
There are [tex]0.015\times 10^{23}[/tex] atoms of carbon
