Answer:
electrons are transferred from the wool shirt to the plastic rod is 4.375 × [tex]10^{12}[/tex] electrons
Explanation:
given data
Amount of charge transferred Q = -0.7 μC = -0.7 × [tex]10^{-6}[/tex] C
electrons of charge e = -1.6 × [tex]10^{-19}[/tex] C
solution
we apply formula here for total charge of electrons that is
Q = n × e ...................2
here n is no of electron that is
n = [tex]\frac{Q}{e}[/tex]
put here value
n = [tex]\frac{-0.7*10^{-6}}{-1.6*10^{-19}}[/tex]
n = 4.375 × [tex]10^{12}[/tex] electrons
so here electrons are transferred from the wool shirt to the plastic rod is 4.375 × [tex]10^{12}[/tex] electrons