p=.59
Explanation:
Using Hardy Weinbeirgh Principle, p can be calculated
p is the frequency of dominant allele in an organism, here plain shells are dominant over striped shells hence dominant allele is homozygous from the question
Dominant homozygous = 136 snails
Recessive allele = 252
Total number of individuals= 136+252
= 388
frequency of individuals with the dominant trait (p^2) = Dominant individual/total individuals
= 130/388
p^2= 0.35
This value 0.35 corresponds to p^2
Since we know that allele is one character of gene
p^2=.35 where underoot x is 0.35
p=[tex]\sqrt{x}[/tex]
p=0.59
Hence the value of p=0.59
