The specific heat capacity of the metal is [tex]3000 J/kg^{\circ}C[/tex]
Explanation:
When a substance absorbs a certain amount of heat, its temperature increases according to the equation:
[tex]Q=mC\Delta T[/tex]
where
Q is the amount of heat absorbed
m is the mass of the substance
C is its specific heat capacity
[tex]\Delta T[/tex] is the increase in temperature of the substance
For the metal in this problem, we have:
m = 0.3 kg
Q = 9000 J
[tex]\Delta T = 10^{\circ}C[/tex]
Therefore, its specific heat is:
[tex]C=\frac{Q}{m\Delta T}=\frac{9000}{(0.3)(10)}=3000 J/kg^{\circ}C[/tex]
Learn more about specific heat capacity:
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