The velocity of the cannonball when it leaves the cannon is 221.29 m/s.
The given parameters;
- mass of the cannonball, m₁ = 6.2 kg
- mass of the cannon, m₂ = 280 kg
- velocity of the cannon, u₁ = 4.9 m/s
Let the velocity of the cannonball when it leaves the cannon = u₁
Apply the principle of conservation of linear momentum to determine the velocity of the cannonball when it leaves the cannon.
m₁u₁ = m₂u₂
6.2u₁ = 280 x 4.9
6.2u₁ = 1372
[tex]u_1 = \frac{1372}{6.2} \\\\u_1 = 221.29 \ m/s[/tex]
Thus, the velocity of the cannonball when it leaves the cannon is 221.29 m/s.
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