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If body fats has a density of 0.94 g/mL and 3.0 liters of fat are removed, how many pounds of fat were removed from the patient?

Respuesta :

nkirotedoreen46

Answer:

6.217 pounds

Explanation:

We are given;

  • Density of body fats 0.94 g/mL
  • Volume of fats removed = 3.0 L

We are required to determine the mass of fats removed in pounds.

We need to know that;

Density = Mass ÷ volume

1 L = 1000 mL, thus, volume is 3000 mL

Rearranging the formula;

Mass = Density × Volume

         = 0.94 g/mL × 3000 mL

         = 2,820 g

but, 1 pound = 453.592 g

Therefore;

Mass = 2,820 g ÷ 453.592 g per pound

         = 6.217 pounds

Thus, the amount of fats removed is 6.217 pounds

asuwafohjames

The mass of the fat removed from the patient is 6.34 pounds

To calculate the mass of the fat (in pounds) removed  from the patient, we use the formula below

Formula:

  • D = m/V.............. Equation 1

Where:

  • D = Density of the body fat
  • V = volume of the body fat
  • m = mass of the body fat.

make m the subject of the equation.

  • m = DV.................. Equation 2

From the question,

Given:

  • D = 0.96 g/mL
  • V = 3 L = 3000 mL

Substitute these values into equation 2

  • m =0.96(3000)
  • m = 2880 g

The convert mass from gram to Ponds

  • m = (2880/454) Pounds = 6.34 pounds.

Hence, The mass of the fat removed from the patient is 6.34 pounds

Learn more about mass here: https://brainly.com/question/15526412

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