Answer:
(A) Average speed is 3.738 m/sec
(B) Average velocity is 0 m/sec
Explanation:
Let the distance from point a and b is d
Speed of person in going from a to b = 5.10 m/sec
So time taken to reach b from a [tex]=\frac{d}{5.10}sec[/tex]
Ans speed in coming back from b to a is 2.95 m/sec
So time taken in coming from b to a [tex]=\frac{d}{2.95}sec[/tex]
(A) Total distance = d+d = 2d
Total time = [tex]t=\frac{d}{5.10}+\frac{d}{2.95}=0.1960d+0.338d=0.5349d[/tex]
Average speed is equal to ratio of total distance and total time
So average speed [tex]=\frac{2d}{0.5349d}=3.738m/sec[/tex]
(B) As the person goes from a to b and then come back to a from b
So displacement = d-d = 0
So average velocity [tex]=\frac{0}{0.5349d}=0m/sec[/tex]
