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A sailboat starts from rest and accelerates at a rate of 0.21 m/s² over a distance of 280 m.
a. Find the magnitude of the boatâs final velocity.
b. Find the time it takes the boat to travel this distance.

Respuesta :

Answer

given,

initial speed of boat, u = 0 m/s

acceleration of the boat, a = 0.21 m/s²

distance,s = 280 m

a) using equation of motion

    v² = u² + 2 a s

    v² = 0² + 2 x 0.21 x 280

    v = √117.6

   v = 10.84 m/s

Final speed of the boat is equal to 10.84 m/s

b) again using equation of motion

    v = u + a t

    10.84 = 0 + 0.21 x t

  0.21 t = 10.84

    t = 51.62 s

time taken by the boat to travel the distance is equal to 51.62 s.