how many electrons were transferred if the total charge of a process is 919.4 C

The electron is known as the subatomic particle which revolves around the nucleus by possessing the negative charge.
when the atoms are involved in the reaction or process these electrons are transferred are gained by the atoms.
Coulomb is the term used to express the charge of the electrons.
In normal 1 coulomb of charge possess 6.25× [tex]10^{18}[/tex] electrons.
So here the total charge of the process is 919.4c in order to find number of electrons transferred is found by the product of 919.4 × 6.25× = 5746.25 × [tex]10^{18}[/tex].
Thus the number of electrons transferred is obtained. the transferred electrons are 5746.25 ×[tex]10^{18}[/tex].

Abdulazeez10 Abdulazeez10 · Answer 2 · 2021-11-18T14:57:05+01:00

The number of electrons that were transferred is 5.746 × 10²¹

From the question,

We are to determine the number of electrons that were transferred.

Using the formula

Q = ne

Where

Q is the total charge

n is the number of electrons

and e is the charge of 1 electron (e = 1.6 × 10⁻¹⁹ C)

From the given information

Q = 919.4 C

Putting this into the formula, we get

919.4 = n × 1.6 × 10⁻¹⁹

∴ n = 919.4 ÷ (1.6 × 10⁻¹⁹)

n = 5.746 × 10²¹

Hence, the number of electrons that were transferred is 5.746 × 10²¹

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