a car travels along a straight road heading east for one hour, then traveling for 30 minutes on another road that leads northeast. if the car has maintained a constant spead of 40 miles per hour, how far is it from the starting position/

Respuesta :

Answer:

55.96 miles

Step-by-step explanation:

Distance = Speed X time

Car first moved east for 1 hr , distance = 40 x 1 = 40 miles

Car then moved north-east for 30 min, distance = 40 x 0.5 = 20 miles

From trigonometry,

sin 45 = [tex]\frac{y}{20}[/tex] ; y = 20 sin 45 ; y= 14.14 miles

cos 45 = [tex]\frac{x}{20}[/tex] ; x = 20 cos 45 ; x = 14.14 miles

using Pythagoras theorem;

[tex]z^{2}[/tex] = [tex]y^{2}[/tex] + [tex](40+x)^{2}[/tex]

    = [tex]14.14^{2}[/tex] + [tex](40+14.14)^{2}[/tex]

     = 3131.08

[tex]z^{2}[/tex] = [tex]\sqrt{3131.08}[/tex]

z = 55.96 miles

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