Harold had a summer lemonade stand where he sold small cups of lemonade for $1.25 and large cups for $2.50. Harold sold a total of 155 cups of lemonade and collected a total of $265, how many cups of each type did he sell.

Respuesta :

98 small cups of lemonade and 57 large cups of lemonade were sold by Harold.

Step-by-step explanation:

Given,

Cost of small cup of lemonade = $1.25

Cost of large cup of lemonade = $2.50

Total cups sold = 155

Total worth of cups = $265

Let,

x be the number of small cups sold

y be the number of large cups sold

According to given statement;

x+y=155      Eqn 1

1.25x+2.50y=265   Eqn 2

Multiplying Eqn 1 by 1.25

[tex]1.25(x+y=155)\\1.25x+1.25y=193.75\ \ \ Eqn\ 3[/tex]

Subtracting Eqn 3 from Eqn 2

[tex](1.25x+2.50y)-(1.25x+1.25y)=265-193.75\\1.25x+2.50y-1.25x-1.25y=71.25\\1.25y=71.25[/tex]

Dividing both sides by 1.25

[tex]\frac{1.25y}{1.25}=\frac{71.25}{1.25}\\y=57[/tex]

Putting y=57 in Eqn 1

[tex]x+57=155\\x=155-57\\x=98[/tex]

98 small cups of lemonade and 57 large cups of lemonade were sold by Harold.

Keywords: linear equation, elimination method

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