Total distance walked by Layla is 300 yards
Solution:
Given that,
Layla is walking in a rectangular park
She walks one side that is 50 yards and then the other side that is 120 yards
Length = 120 yards
Width = 50 yards
Layla develops a cramp in her leg and walks diagonally through the park to head back home
Let us find the length of diagonal of rectangle
[tex]d=\sqrt{w^2+l^2}[/tex]
[tex]d = \sqrt{50^2+120^2}\\\\d = \sqrt{2500+14400}\\\\d = \sqrt{16900}\\\\d = 130[/tex]
Thus length of diagonal is 130 yards
What is the total distance that layla walked?
Given that Final answer is perimeter of the triangle park
The diagonal and length and width forms a right angle triangle
Perimeter of triangle = diagonal length + width + length
Perimeter of triangle = 130 + 50 + 120 = 300
Thus total distance walked by Layla is 300 yards
