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You breathe in 3.0 L of pure oxygen at 298 K and 1,000 kPa to fill your lungs. How many moles of oxygen did you take in? Use the ideal gas law: PV = nRT where R=8.31 L−kPa/mol−K
A. 0.05 MOLE
B. 1.21 MOLES
C. 2.42 MOLES
D. 20.0 MOLES

Respuesta :

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Answer:

Option B.

Explanation:

Let's replace the data given in the formula of Ideal Gases Law.

P. V = n . R . T

3L . 1000kPa = n . 8.31 L.kPa/mol.K . 298K

(3L . 1000 kPa) / ( 8.31 L.kPa/mol.K . 298K) = n

1.21 moles

The number of moles of oxygen by using ideal gas equation is 1.21 moles. Hence, the correct option is B.

Ideal Gas equation

[tex]PV=nRT[/tex]

Here, P is the pressure, V is the volume, n is the number of moles, R is the gas constant, T is the temperature.

We can calculate the number of moles by using the above equation as follows:-

[tex]PV = n R T\\ 1000kPa\times 3L = n \times 8.31 L.kPa/mol.K \times298K\\(3L . 1000 kPa) / ( 8.31 L.kPa/mol.K . 298K) = n\\n=1.21 moles[/tex]

So, the number of moles of oxygen is 1.21 moles.

Learn more about the ideal gas equation here

brainly.com/question/4147359

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