Answer:
It is one-half the area of a rectangle with sides 2 units × 3 units.
Step-by-step explanation:
we have the coordinates of triangle ABC
A(4,5),B(5,2),C(3,2)
Plot the coordinates of triangle to better understand the problem
see the attached figure
step 1
Find the area of triangle ABC
The triangle ABC is an isosceles triangle `(AB=AC)
The area of triangle ABC is
[tex]A=\frac{1}{2}(BC)(AM)[/tex]
we have
[tex]BC=5-3=2\ units[/tex] ---> difference of the x-coordinates
[tex]AM=5-2=3\ units[/tex] ---> difference of the y-coordinates
substitute
[tex]A=\frac{1}{2}(2)(3)=3\ units^2[/tex]
step 2
Find one-half the area of a rectangle with sides 2 units × 3 units
[tex]A=\frac{1}{2} (2)(3)=3\ units^2[/tex]
therefore
The area of triangle ABC is one-half the area of a rectangle with sides 2 units × 3 units
