Respuesta :
Answer: The concentration of chloride ions in the solution obtained is 1.27 M
Explanation:
To calculate the number of moles for given molarity, we use the equation:
[tex]\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}[/tex] .....(1)
- For calcium chloride:
Molarity of calcium chloride solution = 0.439 M
Volume of solution = 194.4 mL
Putting values in equation 1, we get:
[tex]0.439=\frac{\text{Moles of calcium chloride}\times 1000}{194.4}\\\\\text{Moles of calcium chloride}=\frac{(0.439\times 194.4)}{1000}=0.085mol[/tex]
1 mole of calcium chloride produces 2 moles of chloride ions and 1 mole of calcium ion
Moles of chloride ions in calcium chloride = [tex](2\times 0.085)=0.170mol[/tex]
- For aluminum chloride:
Molarity of aluminum chloride solution = 0.497 M
Volume of solution = 363 mL
Putting values in equation 1, we get:
[tex]0.497=\frac{\text{Moles of }AlCl_3\times 1000}{363}\\\\\text{Moles of }AlCl_3=\frac{(0.497\times 363)}{1000}=0.180mol[/tex]
1 mole of aluminum chloride produces 3 moles of chloride ions and 1 mole of aluminum ion
Moles of chloride ions in aluminum chloride = [tex](3\times 0.180)=0.540mol[/tex]
Calculating the chloride ion concentration, we use equation 1:
Total moles of chloride ions in the solution = (0.170 + 0.540) moles = 0.710 moles
Total volume of the solution = (194.4 + 363) mL = 557.4 mL
Putting values in equation 1, we get:
[tex]\text{Concentration of chloride ions}=\frac{0.710mol\times 1000}{557.4}\\\\\text{Concentration of chloride ions}=1.27M[/tex]
Hence, the concentration of chloride ions in the solution obtained is 1.27 M
