In his explanation of the threshold frequency in the photoelectric effect, Einstein reasoned that the absorbed photon must have a minimum energy to dislodge an electron from the metal surface. This energy is called the work function (Φ) of that metal. What is the longest wavelength of radiation (in nm) that could cause the photoelectric effect in each of these metals: (a) calcium, Φ = 4.60 x 10⁻¹⁹ J; (b) titanium, Φ = 6.94 x 10⁻¹⁹ J; (c) sodium, Φ = 4.41 x 10⁻¹⁹ J?

Respuesta :

Answer:

(a)

432 nm

(b)

287 nm

(c)

451 nm

Explanation:

[tex]Energy=\frac {h\times c}{\lambda}[/tex]

Where,  

h is Plank's constant having value [tex]6.626\times 10^{-34}\ Js[/tex]

c is the speed of light having value [tex]3\times 10^8\ m/s[/tex]

[tex]\lambda[/tex] is the wavelength of the light

(a)

Given that:- Energy = [tex]4.60\times 10^{-19}\ J[/tex]

[tex]4.60\times 10^{-19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{\lambda}[/tex]

[tex]4.6\times \:10^{26}\times \lambda=1.99\times 10^{20}[/tex]

[tex]\lambda=4.32\times 10^{-9}\ m[/tex] = 432 nm

(b)

Given that:- Energy = [tex]6.94\times 10^{-19}\ J[/tex]

[tex]6.94\times 10^{-19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{\lambda}[/tex]

[tex]6.94\times \:10^{26}\times \lambda=1.99\times 10^{20}[/tex]

[tex]\lambda=2.87\times 10^{-9}\ m[/tex] = 287 nm

(c)

Given that:- Energy = [tex]4.41\times 10^{-19}\ J[/tex]

[tex]4.41\times 10^{-19}=\frac{6.626\times 10^{-34}\times 3\times 10^8}{\lambda}[/tex]

[tex]4.41\times \:10^{26}\times \lambda=1.99\times 10^{20}[/tex]

[tex]\lambda=4.51\times 10^{-9}\ m[/tex] = 451 nm