Respuesta :
Answer:
9.09*10^-13
Explanation:
Certain values of the problem where omitted,however the omitted values were captured in the solution.
Step1:
Avogadro's number (NA) I = 6.02*10^23 atoms/mole.
Step2:
To determine the number of moles of copper that are present, thus: Using the mass and atomic mass :
n = m/A
n = 50.0g/63.5g/mol
Therefore, since the are 29 protons per atom, I the number of protons can be determined as follows :
Np = nNA*29 protons /atom
Np=(50.0gm/63.5g/mol)(6.02*10^23 atoms/mol) * (29 protons / C u atom)
Np= 1.375*10^25 protons
Note that there are same number of electrons as protons in a neutral atom, I therefore the removal of electrons to give the copper a net change, hence the result is 1.375*10^25
Step3:
To determine the number electrons , removed to leave a net charge of 2.00Uc, then remove -2 .00Uc of charge, so that the number of electrons to be removed are as follows :
Ne(removed)=
Q/qe= -2.00*10^-6c/-1.60* 10^-19c
Ne(removed)=1.25*10^13 electrons removed
Step4:
To calculate the fraction of copper's electron by taking the ratio of the number of electrons initially present:
Ne,removed/Ne,initially=1.25*10^13/ 1.37*10^25 = 9.09*10^-13
