To solve this problem we will apply the linear motion kinematic equations.
The equation that describes the position as a function of the initial velocity, acceleration and time is given by the relation
[tex]s = v_0 t +\frac{1}{2} at^2[/tex]
Here,
[tex]v_0 =[/tex] Initial velocity
t = Time
a = Acceleration, at this case due to gravity
There is not initial velocity then we have that the equation to the given time is
[tex]s = \frac{1}{2} (9.8)(6.8)^2[/tex]
[tex]s = 226.8m[/tex]
If the ball is held at a height of 1m before it is dropped, we have that the Building height is
[tex]h = 226.8-1[/tex]
[tex]h = 225.8m[/tex]
