Respuesta :
Answer:
a) Probability that Julia misses two shots in a row = [tex]\frac{1}{2}\frac{1}{5} =\frac{1}{10}[/tex]
b) We can use the complement rule on this case. Let X the number of shoots successful, we want this probability:
[tex] P(X \geq 1)[/tex]
And using the complement rule we have this:
[tex] P(X \geq 1) = 1-P(X<1) = 1-P(X=0)[/tex]
And P(X=0) correspond to the probability that Julia misses two shots in a row founded on part A so then we have:
[tex] P(X\geq 1) = 1- \frac{1}{10}= \frac{9}{10}[/tex]
Step-by-step explanation:
Part a
For this case we know that Julia enjoys shooting paper balls into the basket across her office.
She misses the first shot 50% of the time.
Probability that Julia misses the first shot = [tex]\frac{1}{2}[/tex]
When she misses on the first shot, she misses the second shot 20% of the time.
Probability that Julia misses the second shot = [tex]\frac{1}{5}[/tex]
For this case we need to find the probability of missing two shots in a row
So we can multiple the two probabilities like this
Probability that Julia misses two shots in a row = [tex]\frac{1}{2}\frac{1}{5} =\frac{1}{10}[/tex]
Part b
For this case we want probability of making at least one successful throw
And we can use the complement rule on this case. Let X the number of shoots successful, we want this probability:
[tex] P(X \geq 1)[/tex]
And using the complement rule we have this:
[tex] P(X \geq 1) = 1-P(X<1) = 1-P(X=0)[/tex]
And P(X=0) correspond to the probability that Julia misses two shots in a row founded on part A so then we have:
[tex] P(X\geq 1) = 1- \frac{1}{10}= \frac{9}{10}[/tex]
Answer:
Part A:
The probability of Julia missing two shots in a row is, = 1/2 1/5= 1/10 --- 10%
Part B:
The probability of Julia making at least one successful throw is= 9/10 --- 90%
Step-by-step explanation:
Just took the test :)
FLVS
Hope it helps :))
Pls mark brainliest <3
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Tori
