If you fire a projectile from the ground, it hits the ground some distance R away (called "the range"). If you keep the launch angle fixed, but double the initial launch speed, what happens to the range?

Respuesta :

Answer:

range becomes 4 times

Explanation:

We know that the range of a projectile is given as:

[tex]R=\frac{u^2.\sin(2\theta)}{g}[/tex]

where:

[tex]R=[/tex] range of the projectile

[tex]u=[/tex] initial velocity of projectile

[tex]\theta=[/tex] initial angle of projection form the horizontal

g = acceleration due to gravity

When the initial velocity of launch is doubled:

[tex]R'=\frac{(2u)^2.\sin(2\theta)}{g}[/tex]

[tex]R'=\frac{4u^2.\sin(2\theta)}{g}[/tex]

[tex]R'=4R[/tex]

range becomes 4 times

Answer:

4 times

Explanation: