Respuesta :

[tex]2x^2-8x+8=0 \\ d= b^{2} -4ac \\ =(-8)^2-4 \times 2 \times 8 \\ =64-64 \\ =0[/tex]
Since the discriminant is 0, the equation has one real number solution.
slamcg

Answer:

A. The discriminant is equal to 0, which means the equation has no real number solutions.

Step-by-step explanation:

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