Alice and Amy decide to meet at a party. From a corner of the party hall, Amy spots Alice at the corner of the hall diagonally opposite her. If the party hall is a rectangle that measures 100 feet by 60 feet, what is the shortest distance Amy has to walk to reach Alice? Round your answer to the nearest foot.

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Use the Pythagorean theorem, [tex]c= \sqrt{a^{2} + b^{2} }[/tex], to answer this problem. Because Alice and Amy are diagonally opposite each other in two corners of the room, the shortest way Amy can reach Alice is to walk straight to her in a diagonal line. The length of this diagonal line is equal to [tex]\sqrt{100^{2} + 60^{2} }[/tex]. This length is equal to 117 ft.

The answer is C. 117 feet I did the test so this is correct.