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How many moles of ions would you expect in an aqueous solution containing one mole of chromium(III) chloride? Hint: write out the dissociation equation for chromium(III) chloride to determine how many ions are present.

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Answer:

Four  

Explanation:

AlCl₃(aq) ⟶ Al³⁺(aq) + 3Cl⁻(aq)

One mole of AlCl₃  produces 1 mol of Al³⁺ and 3 mol of Cl⁻.

That's four moles of ions.