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a 6.0 x 10^-2 kg tennis ball moves at velocity of 12 ,/s. the ball is struck by a racket, causing it to rebound in the opposite direction at a speed of 18 m/s. what is the change in the ball's momentum

Respuesta :

opudodennis

Answer:

1.8 Kg.m/s

Explanation:

Change in momentum is given by

[tex]\triangle p= m(v-u)[/tex] where [tex]\triangle p[/tex] is the change in momentum, m is the mass of the ball, v is the final velocity of the ball and u is the initial velocity of the ball.

Substituting [tex]6\times 10^{-2} Kg[/tex] for m, -18 m/s for v since it's in opposite direction and 12 m/s for u then

[tex]\triangle p[/tex][tex]\p=6\times 10^{-2} Kg (-18 m/s-12 m/s)= -1.8 Kg.m/s[/tex]

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