contestada

(I) At room temperature, an oxygen molecule, with mass of –26 5.31 10 kg, typically has a kinetic energy of about –21 6.21 10 J . How fast is it moving?

Respuesta :

Answer:

0.484 m/s

Explanation:

Kinetic energy is given by

KE = mv²/2

m = mass of the oxygen molecule = 5.31 x 10⁻²⁰ kg

K.E = kinetic energy of the oxygen molecule = 6.21 x 10⁻²¹ J

v = ?

(6.21 x 10⁻²¹) = (5.31 x 10⁻²⁰) v²/2

v² = 2 × (6.21 x 10⁻²¹)/(5.31 x 10⁻²⁰) = 0.2339

v = 0.484 m/s

Otras preguntas