Respuesta :
Answer:
The true statements are:
The solution is acidic
The pH of the solution is 14.00 - 10.53.
[tex]10^{-10.53}=[OH^-][/tex]
Explanation:
The pH of the solution is defined as negative logarithm of hydrogen ion concentration present in the solution .
[tex]pH=-\log[H^+][/tex]
- The pH value more 7 means that hydrogen ion concentration is less ,alkaline will be the solution.
- The pH value less 7 means that hydrogen ion concentration is more ,acidic will be the solution.
- The pH value equal to 7 indicates that the solution is neutral.
The pOH of the solution is defined as negative logarithm of hydroxide ion concentration present in the solution .
[tex]pOH=-\log[OH^-][/tex]
The pOH of the solution = 10.53
[tex]10.53=-\log[OH^-][/tex]
[tex]10^{-10.53}=[OH^-][/tex]
The pH of the solution = ?
[tex]pH+pOH=14[/tex]
[tex]pH=14-pOH=14-10.53=3.47[/tex]
Here, the pH of the solution is less than 7 which means that solution acidic.
All the statements are true.
The statements that are true are:
- The solution is acidic.
- The pH of the solution is 14.00 - 10.53.
and
- [OH−] = 10^−10.53 M
From the question,
We are to determine which of the given statements is or are true.
From the given information
A solution at 25 ∘C has pOH = 10.53.
To determine which of the given statements is or are true,
we will determine if the solution is acidic, determine the pH of the solution and as well determine the [OH−] for the solution
First, we will determine the pH of the solution
From the formula
pH + pOH = 14
Then,
pH = 14 - pOH
∴ pH of the solution = 14 - 10.53
pH of the solution = 3.47
Since, the value of the pH is less than 7, then the solution is acidic.
Now, we will determine the value of [OH−] in the solution
From the formula
pOH = -log[OH−]
Then,
[OH−] = 10^(-pOH)
∴ [OH−] for the solution = 10^(-10.53) M
From above, we can observe that,
The solution is acidic.
The pH of the solution is 14.00 - 10.53.
and
[OH−] = 10^−10.53 M
Hence, all the statements are true.
The statements that are true are:
- The solution is acidic.
- The pH of the solution is 14.00 - 10.53.
and
- [OH−] = 10^−10.53 M
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