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the student determines the molar mass of the gas to be 64 g mol-1. write the expression (set-up) for calculating the percent error in the experimental value, assuming that the unknown gas is butane (molar mass 58 g mol-1). calculations are not required

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Answer:

Percentage error = [tex]\frac{(64 - 58)}{58}[/tex] x 100%

Explanation:

In order to calculate the percentage error in the student's calculation, the following formula will be used:

Percentage error = [tex]\frac{(experimental molar mass - theoretical molar mass)}{theoretical molar mass}[/tex] x 100%

experimental molar mass = 64 g/mol

theoretical molar mass = 58 g/mol

Hence, the expression becomes:

Percentage error = [tex]\frac{(64 - 58)}{58}[/tex] x 100%

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