Respuesta :
Answer:
11.613 M is the molarity of the sulfuric acid solution.
Explanation:
The reaction taking place is neutralization reaction:[tex]H_2SO_4(aq)+2NaOH(aq)\rightarrow Na_2SO_4(aq)+2H_2O(l)[/tex]
To calculate the concentration of acid, we use the equation given by neutralization reaction:
[tex]n_1M_1V_1=n_2M_2V_2[/tex]
where,
[tex]n_1,M_1\text{ and }V_1[/tex] are the n-factor, molarity and volume of acid which is [tex]H_2SO_4[/tex]
[tex]n_2,M_2\text{ and }V_2[/tex] are the n-factor, molarity and volume of base which is NaOH.
We are given:
[tex]n_1=2\\M_1=?\\V_1=1.50 mL\\n_2=1\\M_2=1.47 M\\V_2=23.70 mL[/tex]
Putting values in above equation, we get:
[tex]2\times M_1\times 1.50 mL=1\times 1.47 M\times 23.70 ml[/tex]
[tex]M_1=\frac{1\times 1.47 M\times 23.70 ml}{2\times 1.50 ml}=11.613 M[/tex]
11.613 M is the molarity of the sulfuric acid solution.
