Respuesta :
Answer:
(a). The mode of inheritance is quantitative inheritance.
There are 3 gene pairs at work.
Genotypes designating Emma 30cm, Harvey 6cm and their 18cm offspring are Emma as TT, Harvey as Tt and 18cm offspring as Tt since the phenotype is about height T.
(b) The phenotype ratio of 18cm of F1 and 6cm of F2 is 1:1.
Explanation:
(a) Quantitative inheritance is the mode of inheritance that deals with additive action of many genes resulting into a traits such as height, showing contiguous variation.
The frequency of either extreme phenotype give us n, the number of gene pairs.
Frequency of one extreme phenotype = (1/4)n = 1/64.
Number of gene pairs =
log 64/log 4 = 3.
Therefore 3 gene pairs were at work.
The phenotype here is about height either tall, T or short t. There genotype designation will be given as 30cm of Emma as TT homozygous tall, 6cm of Harvey as tt homozygous short, and 18cm of offspring as Tt, heterozygous tall.
(b) The phenotype of 18cm of F1 and 6cm of F2 offspring will come the crossing of 18cm, Tt of F1 and 6cm, tt of F2 to give 4 offspring as Tt, Tt, tt, tt.
Therefore, comparing the phenotype ratio (tall or short) we have 2:2 which gives 1:1.
The way in which tail length was inherited is through a mode of inheritance known as quantitative inheritance.
What is quantitative inheritance?
Quantitative inheritance can be defined as a mode of inheritance which involves an additive action (combination) of several genes, so as to produce distinctive inheritable traits such as height while showing contiguous variation.
Frequency of an extreme phenotype = (1/4)n
Frequency of an extreme phenotype = 1/64.
Number of gene pairs = log64/log4
Number of gene pairs = 3.
How to determine the phenotypic ratio?
The phenotype of 18 cm (F₁) and 6cm (F₂) offspring would result in the crossing of Tt and tt, so as to produce four (4) offspring:
Tt, Tt, tt, and tt.
Hence, the phenotype ratio (tall or short) is given by:
Phenotypic ratio = 2:2
Phenotypic ratio = 1:1.
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