Answer : The value of equilibrium constant (Kp) is, [tex]7.94\times 10^{-3}[/tex]
Explanation : Given,
Partial pressure of A at equilibrium = 6.70 atm
Partial pressure of B at equilibrium = 10.1 atm
Partial pressure of C at equilibrium = 3.60 atm
The given chemical reaction is:
[tex]2A(g)+B(g)\rightarrow C(g)[/tex]
The expression for equilibrium constant is:
[tex]K_p=\frac{(p_{C})}{(p_{A})^2\times (p_{B})}[/tex]
Now put all the given values in this expression, we get:
[tex]K_p=\frac{(3.60)}{(6.70)^2\times (10.1)}[/tex]
[tex]K_p=7.94\times 10^{-3}[/tex]
Thus, the value of equilibrium constant (Kp) is, [tex]7.94\times 10^{-3}[/tex]
