Answer:
a) [tex]\Delta s=443037.9747\ J.K^{-1}[/tex]
b) [tex]\Delta s=31868131.8681\ J.K^{-1}[/tex]
Explanation:
a)
Given:
amount of heat transfer occurred,[tex]dQ=3.5\times 10^6\ J[/tex]
initial temperature of car, [tex]T_i=36.5+273=309.5\ K[/tex]
final temperature of car, [tex]T_f=44.4+273=317.4\ K[/tex]
We know that the change in entropy is given by:
[tex]\Delta s=\frac{dQ}{T_f-T_i}[/tex]
[tex]\Delta s=\frac{3.5\times 10^6}{(44.4-36.5)}[/tex] (heat is transferred into the system of car)
[tex]\Delta s=443037.9747\ J.K^{-1}[/tex]
b)
amount of heat transfer form the system of house, [tex]dQ=5.8\times 10^8\ J[/tex]
initial temperature of house, [tex]T_i=23.5+273=296.5\ K[/tex]
final temperature of house, [tex]T_f=5.3+273=278.3\ K[/tex]
[tex]\Delta s=\frac{dQ}{T_f-T_i}[/tex]
[tex]\Delta s=\frac{5.8\times 10^8}{278.3-296.5}[/tex]
[tex]\Delta s=31868131.8681\ J.K^{-1}[/tex]
