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A ball is tossed vertically upward from a height of 2 m above the ground with an initial velocity of 10 m/s. What will the velocity of the ball be just before it hits the ground?

Respuesta :

Answer:7.746m/s

Explanation:V^2=U^2-2gh

g=10m/s(acceleration due to gravity)

V^2=10^2-2*10*2

V^2=60

V=√60=7.746.

THE VELOCITY OF THE BALL JUST BEFORE IT HIT THE GROUND =V(final velocity)

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