Answer:
P ( X < 4 ) = 0.3015
Step-by-step explanation:
Given:
- The ratings for current lives on a scale 0 - 10 were normally distributed with parameters mean (u) and standard deviation (s).
u = 5.3
s = 2.5
Find:
Find the probability that a randomly selected study participant's response was less than 4.
Solution:
- Declare a random variable X that follows a normally distribution with parameters u and s, mean and standard deviation respectively.
X~N( 5.3 , 2.5 )
- To determine the probability of the rating to be less than 4 for a randomly selected study participant's response we have:
P ( X < 4 )
- Compute the Z-score value for the limit given:
P ( Z < (4 - 5.3) / 2.5 )
P ( Z < -0.52 )
- Use the Z-Table to calculate the above probability as follows:
P ( Z < -0.52 ) = 0.3015
- Hence, the required probability is equivalent to Z-score value probability:
P ( X < 4 ) = P ( Z < -0.52 ) = 0.3015