Explanation:
It is known that the relation between speed and distance is as follows.
velocity = [tex]\frac{distance}{time}[/tex]
As it is given that velocity is 6 m/s and distance traveled by the bear is (d + 29). Therefore, time taken by the bear is calculated as follows.
[tex]t_{bear} = \frac{(d + 29)}{6 m/s}[/tex] ............. (1)
As the tourist is running in a car at a velocity of 4.2 m/s. Hence, time taken by the tourist is as follows.
[tex]t_{tourist} = \frac{d}{4.2}[/tex] ............. (2)
Now, equation both equations (1) and (2) equal to each other we will calculate the value of d as follows.
[tex]t_{bear} = t_{tourist}[/tex]
[tex]\frac{(d + 29)}{6 m/s}[/tex] = [tex]\frac{d}{4.2}[/tex]
4.2d + 121.8 = 6d
d = [tex]\frac{121.8}{1.8}[/tex]
= 67.66
Thus, we can conclude that the maximum possible value for d is 67.66.
