Consider the four points used in Problem 1: (-9,13), (-3, 9), (3, 6) and (9, 1) Three out of four of these points lie on one line. Which one of the four points does not lie on the same line as the other three? Justify your answer using slope. b) Find the equation of the line that contains three out of the four points

Respuesta :

Answer:

a) ( 3 , 6 )

b) y = -2*x / 3 + 7

Step-by-step explanation:

Given:

- The four points are:

                        (-9,13), (-3, 9), (3, 6) and (9, 1)

- Three points lie on the same line.

Find:

Which one of the four points does not lie on the same line as the other three?

Solution:

- Compute the slope between each pair of point:

                                 (-9,13), (-3, 9)

                        m_1 = ( 9 - 13 ) / ( -3 + 9 ) = - 2/3

                                 (-9,13), (3, 6)

                        m_2 = ( 6 - 13 ) / ( 3 + 9 ) = - 0.5833

                                 (-9,13), (9, 1)

                        m_3 = ( 1 - 13 ) / ( 9 + 9 ) = - 2/3

- We see that m_1 = m_3 ≠ m_2 . Hence, point ( 3 ,6 ) does not lie on the same line.

- The equation of line is expressed as:

                        y = m*x + C

                        m = -2/3

                        y = -2*x / 3 + C

                        1 = -2*9 / 3 + C ....... ( 9 , 1 )

                        C = 7

- The equation of the line is:

                        y = -2*x / 3 + 7

    Points A(-9, 13), B(-3, 9) and D(9, 1) are colinear.

b). Equation of the line passing through these points will be [tex]y=-\frac{2}{3}x+7[/tex]

Property for the colinear points:

  • If three points are colinear, slope of the lines joining these points will be equal.
  • Slope of a line joining two points [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] is given by,

        [tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Given points in the question,

A(-9, 13), B(-3, 9), C(3, 6) and D(9, 1)

If the slopes of the lines joining these points are same, points will be colinear.

Slope of AB = [tex]\frac{13-9}{-9+3}=-\frac{2}{3}[/tex]

Slope of AC = [tex]\frac{13-6}{-9-3}=-\frac{7}{12}[/tex]

Slope of AD = [tex]\frac{13-1}{-9-9}=-\frac{2}{3}[/tex]

Since, slopes of AB and AD are equal, points A, B and D will be colinear.

b). Let the equation of the line passing through A, B and D is,

    y - y' = m(x - x')

    Since, this line passes through D(9, 1) and slope = [tex]-\frac{2}{3}[/tex]

    Equation of the line → [tex]y-1=-\frac{2}{3}(x-9)[/tex]

                                    [tex]y=-\frac{2}{3}x+6+1[/tex]

                                    [tex]y=-\frac{2}{3}x+7[/tex]

       Therefore, points A(-9, 13), B(-3, 9) and D(9, 1) are colinear and equation of the line passing through these points will be [tex]y=-\frac{2}{3}x+7[/tex].

Learn more about the slope of a line here,

https://brainly.com/question/490077?referrer=searchResults

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