contestada

A block of mass 22 kg is sliding along the ice at constant speed 5.0 m/s. Just ahead of it is a block of mass 29 kg sliding in the
same direction at constant speed 4.6 m/s. When the two blocks collide, the 29-kg block travels at a new speed of 7.2 m/s. What is
the new speed of the 22-kg block?

Respuesta :

The new speed of 22 kg block is 1.57 m/s

Explanation:

Given-

Mass, [tex]m_{1}[/tex]= 22 kg

speed, [tex]v_{1}[/tex] = 5 m/s

[tex]m_{2}[/tex] = 29 kg

[tex]v_{2i[/tex] = 4.6 m/s

New speed of [tex]m_{2}[/tex], [tex]v_{2f}[/tex] = 7.2 m/s

New speed of [tex]m_{1}[/tex], [tex]v_{1f}[/tex] = ?

This is the case of elastic collision.

So,

[tex]M_{1}[/tex] X  [tex]V_{1i}[/tex]+ [tex]M_{2}[/tex] X [tex]V_{2i}[/tex] = [tex]M_{1}[/tex] X [tex]V_{1f}[/tex] + [tex]M_{2}[/tex] X [tex]V_{2f}[/tex]

22 X 5 + 29 X 4.6 = 22 X[tex]V_{1f}[/tex] + 29 X 7.2

22 [tex]V_{1f}[/tex] + 208.8 = 243.4

22 [tex]V_{1f}[/tex]= 34.6

[tex]V_{1f}[/tex]= 1.57 m/s

Therefore, the new speed of 22 kg block is 1.57 m/s