Respuesta :
Answer:
TRUE. The potential of a negatively charged conductor must be negative
Explanation:
Let's examine each statement
The positively charged proton moves in the direction of the electric field, the power and the electric field are related
ΔU = - E ds
[tex]U_{f}[/tex] - U₀ = - E ds
E = (U₀ –U_{f}) / s
To have a positive electric field the initial potential must be greater than the final potential, so the proton moves from a greater potential to a smaller one.
This statement is FALSE
The second statement
The potential has the same sign as the elective charge.
This statement is TRUE
A proton tends to move to a region of higher potential is False, while The potential of a negatively charged conductor must be negative is True.
Electric Potential:
The proton is a positively charged particle and moves in the direction of the electric field lines.
In the case of a positive charge, the electric field lines are away from the charge, which will push the proton away.
We know that the potential is inversely proportional to distance.
Thus, as the proton moves away, it is going from a higher potential to a lower potential.
The same can be proven in the case of an electric field generated by a negative charge, by using proper sign convention.
So the statement that a proton tends to go from a region of low potential to a region of high potential is FALSE
The potential has the same sign as the electric charge.
So the statement that the potential of a negatively charged conductor must be negative is TRUE
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