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Fluid originally flows through atube at a rate of 200 cm3/s. Toillustrate the sensitivity of the Poiseuille flow rate to variousfactors, calculate the new flowrate for the following changes with all other factors remaining the same as in the original conditions: A new fluid with 6.00 times greater viscosity is substituted. Poiseuille flow is given by:

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Answer:

[tex]Q_{2}=1200cm^{3}/s[/tex]

Explanation:

Given data

Q₁=200cm³/s

We know that:

[tex]F=n\frac{vA}{l}\\[/tex]

can be written as:

ΔP=F/A=n×v/L

And

Q=ΔP/R

As

n₂=6.0n₁

So

Q=ΔP/R

[tex]Q=\frac{nv}{lR}\\ \frac{Q_{2}}{n_{2}}= \frac{Q_{1}}{n_{1}}\\ Q_{2}=\frac{Q_{1}}{n_{1}}*(n_{2})\\Q_{2}=\frac{200}{n_{1}}*6.0n_{1}\\ Q_{2}=1200cm^{3}/s[/tex]

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