Answer : The final temperature of the aluminum is, [tex]155.9^oC[/tex]
Explanation :
Formula used :
[tex]q=m\times c\times (T_{final}-T_{initial})[/tex]
where,
q = heat = 3600 cal = 15062.4 J (1 cal = 4.184 J)
m = mass of aluminum = 125 g
c = specific heat of aluminum = [tex]0.90J/g^oC[/tex]
[tex]T_{final}[/tex] = final temperature = ?
[tex]T_{initial}[/tex] = initial temperature = [tex]22^oC[/tex]
Now put all the given values in the above formula, we get:
[tex]15062.4J=125g\times 0.90J/g^oC\times (T_{final}-22)^oC[/tex]
[tex]T_{final}=155.9^oC[/tex]
Thus, the final temperature of the aluminum is, [tex]155.9^oC[/tex]
