How much work does it take for an external agent to move a 45.0-nC charge from a point on the +x-axis, 3.40 cm from the origin to a point halfway between the 41.0-nC and 52.0-nC charges?

Respuesta :

Answer:

The work done on the 45.0nC charge is 2.24×10^-3J. The detailed solution can be found in the attachment below.

Explanation:

The Problem solution makes use of the potential energy relationship between the charges. This solution assumes the distance as shown in the diagram. For a different distance arrangement adjustments should be made appropriately.

Ver imagen akande212