dr un grupo de alumnos 4/6 van a participar en un concurso de danza. la mitad de ellos presentará una danza folclórica y ka otra mitad, una pieza de danza clásica. ¿que parte del total de alumnos participará en cada una de las dos piezas de danza?

Respuesta :

x = grupo de alumnos

4/6x = danza
1/2(4/6x) = folclórica/clásica

[tex] \frac{4}{6} * \frac{1}{2} = \frac{2}{6} [/tex]
[tex]= \frac{1}{3} x [/tex]

La respuesta es 1/3


The total number of students who will participate in each of the two dance pieces are given as 1.33x. See the explanation for the math problem below.

What is the solution to the above problem?

We start  off by indicating that the number of students or group of students  = x

Recall that 4/6 students are going to participate in the dance context.

Therefore (4/6)x = participants in a dance text.

Half will present a folk dance and the other half a classical dance.

That is:

1/2 * (4/6)x = Folk

1/2 * (4/6)x = Classical

Therefore total number of students that will participate  in both types of dances =

1/2 * (4/6)x + 1/2 * (4/6)x

= 2/3x + 2/3x

=1.33x

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