Respuesta :

149 g of cobalt are present in 1.52 x [tex]10^{24}[/tex] atoms of cobalt.

Explanation:

One mole of an atom is equal to the Avagadro number of the atom.

              [tex]1 \ mol \ of \ Co = 6.023\times10^{23} atoms\ of \ Co[/tex]

The number of atoms per mol is divided by the given atoms of Cobalt.

                =  [tex](1.52 \times 10^{24}) \times[/tex] [tex]\frac{1 \ mol\ Co}{6.023 \times10^{23}\ atoms\ Co}[/tex]

                = 2.52 mol of Co

To covert, the moles into grams multiply the mole value by its molar mass

The Molar mass of Cobalt is 58.93

                = 2.52 [tex]\times[/tex] 58.93

                = 149 g.