Answer: The equilibrium constant for the given reaction is 1.33
Explanation:
We are given:
Equilibrium concentration of ammonia = 2 M
Equilibrium concentration of nitrogen gas = 3 M
Equilibrium concentration of hydrogen gas = 1 M
For the given chemical equation:
[tex]N_2+3H_2\rightleftharpoons 2NH_3[/tex]
The expression of [tex]K_{eq}[/tex] for above equation follows:
[tex]K_{eq}=\frac{[NH_3]^2}{[N_2][H_3]^3}[/tex]
Putting values in above equation, we get:
[tex]K_{eq}=\frac{(2)^2}{3\times (1)^3}\\\\K_{eq}=1.33[/tex]
Hence, the equilibrium constant for the given reaction is 1.33
