Answer:
8
Step-by-step explanation:
Given that in a sample of n = 6 scores, the smallest score is X = 3, the largest score is X = 10
Mean = 6
Since mean = 6 we get sum of all the 6 scores = [tex]6(6) = 36[/tex]
Now II part says 10 is changed to 20
i.e. original sum = 36
Changed value = 10
Adjusted value =26
Add: new value =22
New sum =48
So we have sum = 48
New mean= [tex]\frac{48}{6} =8[/tex]
(This can also be done using the formula
old mean + positive change in one score/6)